Saving a Person's Info Locally - Printable Version +- Jellyfin Forum (https://forum.jellyfin.org) +-- Forum: Support (https://forum.jellyfin.org/f-support) +--- Forum: General Questions (https://forum.jellyfin.org/f-general-questions) +--- Thread: Saving a Person's Info Locally (/t-saving-a-person-s-info-locally) |
Saving a Person's Info Locally - PriestMarmore - 2024-05-25 I only have my stuff offline and I know there are plugins for getting information about the actors (but it's not for Hollywood actors if you know what I mean). Here's my first problem. I know there are folders for each person and when I move a photo to someone's folder, and that photo is named "folder", the Primary photo of that actor will change, however if I do the same with a photo named backdrop, it will not change on jellyfin. Why is that? Do I really need to upload it through jellyfin. Secondly, I thought about creating a program that would read a folder and that folder contained 3 things: a Primary photo, a Backdrop and a .txt file with info about the person. I wanted that program to change the info of the actor in question based on what was there on the folder. Does that exist? Is there any way I can have information on a .txt file or a .nfo and I'm able to run a program that updates that information about the actor in question? I wrote a bit of code, I'll leave bellow, but it's not working. This is only for the information, I didn't touch on the photos yet import os import requests import json # Jellyfin server details jellyfin_url = 'http://localhost:8096' api_key = '' # Function to read person info from the info.txt file def read_person_info_from_file(file_path): person_info = {} with open(file_path, 'r', encoding='utf-8') as f: lines = f.readlines() for line in lines: if ':' in line: key, value = line.split(':', 1) person_info[key.strip()] = value.strip() return person_info # Function to update person information def update_person_info(person_id, new_info): headers = { 'X-Emby-Token': api_key, 'Content-Type': 'application/json' } url = f'{jellyfin_url}/Items/{person_id}' response = requests.post(url, headers=headers, data=json.dumps(new_info)) print(f'Updating person info at {url} with data: {json.dumps(new_info, indent=2)}') print(f'Response: {response.status_code} - {response.text}') if response.status_code == 204: print('Person information updated successfully.') else: print(f'Failed to update person information: {response.status_code} - {response.text}') # Example usage folder_path = r'D:\Quick Access\Downloads\jelly' info_file_path = os.path.join(folder_path, 'info.txt') person_id = '' # Tom Cruise's person ID person_info = read_person_info_from_file(info_file_path) # Prepare person info payload update_info = { "Name": person_info.get("Name"), "Overview": person_info.get("Overview"), "PremiereDate": person_info.get("BirthDate"), "ProductionYear": int(person_info.get("BirthDate")[:4]), # Assuming the birth year is the production year "Type": "Person" } update_person_info(person_id, update_info) RE: Saving a Person's Info Locally - HERIGROSIR - 2024-07-13 The solution you are waiting for is here, at the bottom of the information https://forum.jellyfin.org/t-feature-requests |